# How do I prove that #1/(sec A+1)+1/(sec A-1)#=#2 csc A cot A# ?

##### 1 Answer

Taking the Lowest common Multiple,

As you may be aware,

Simplifying,

Now

and

Substituting,

which can be written as

Now

Substituting, we get

Taking the Lowest common Multiple,

As you may be aware,

Simplifying,

Now

and

Substituting,

which can be written as

Now

Substituting, we get